Answered

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What is the center and radius of the circle?
(x-3)2 + y² = 4

Sagot :

semsee45

Answer:

center = (3, 0)

radius = 2

Step-by-step explanation:

Standard equation of a circle:  [tex]\sf (x-h)^2+(y-k)^2=r^2[/tex]

(where (h, k) is the center of the circle and r is the radius)

Given equation:

[tex]\sf (x-3)^2+y^2=4[/tex]

Rewrite in standard form:

[tex]\sf \implies (x-3)^2+(y-0)^2=2^2[/tex]

Therefore

  • center = (3, 0)
  • radius = 2
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