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find the first derivative of x^2+y^2=25​

Sagot :

Answer:

[tex]\frac{dy}{dx}=-\frac{x}{y}[/tex]

Step-by-step explanation:

Use implicit differentiation:

[tex]x^2+y^2=25\\\\2x+2y\frac{dy}{dx}=0\\ \\2y\frac{dy}{dx}=-2x\\ \\\frac{dy}{dx}=-\frac{x}{y}[/tex]

Remember to treat "y" as a constant in implicit differentiation and include dy/dx.

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