The length of the side AB and side CD of kite abcd which is shown in the figure is 15 units and 20 units respectively.
Pythagoras theorem says that in a right angle triangle the square of hypotenuse side is equal to the sum of square of other two legs of right angle triangle.
Let the intersection point of dignoals is O. The figure of the kite ABCD, is attached below. The sides of the kite ABCD, are,
[tex]AO=12\\OB=9\\CO=12\\OD=16[/tex]
In the triangle AOB using the pythagours theorem,
[tex]AB=\sqrt{(AO)^2+(OB)^2}\\AB=\sqrt{(12)^2+(9)^2}\\AB=\sqrt{225}\\AB=15[/tex]
Similarly, in the triangle DOC using the pythagours theorem,
[tex]CD=\sqrt{(CO)^2+(OD)^2}\\CD=\sqrt{(12)^2+(16)^2}\\CD=\sqrt{400}\\CD=20[/tex]
Thus, the length of the side AB and side CD of kite abcd which is shown in the figure is 15 units and 20 units respectively.
Learn more about the Pythagoras theorem here;
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