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Sagot :
The value of sin(80°)cos(20°) – cos(80°)sin(20°) using the trignometry property is √3/2.
What is difference formula in trignometry?
The difference formula in trignometry for the sine funciton is given as,
[tex]\sin(A-B)=\sin(A)\cos(B) -\cos(A)\sin(B)[/tex]
The trignometric equation given in the problem is,
[tex]\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)[/tex]
Compare this equation with the above eqution, we get,
[tex]A=80^o\\B=20^o[/tex]
Thus, this equation can be written as,
[tex]\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)=\sin(80-20)\\\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)=\sin(60)\\\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)=\dfrac{\sqrt{3}}{2}[/tex]
Hence, the value of sin(80°)cos(20°) – cos(80°)sin(20°) using the trignometry property is √3/2.
Learn more about the difference formula in trignometry here;
https://brainly.com/question/2142049
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