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Kindly solve this question

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Sagot :

EPSTER1

Answer:

x=-1/7

Step-by-step explanation:

[tex]\frac{3x-1}{3} -\frac{2x}{x-1} =x[/tex]

[tex]\frac{(3x-1)(x-1)}{3x-3} -\frac{2x(3)}{3x-3} =x[/tex]

[tex]\frac{3x^2-4x+1}{3x-3} -\frac{6x}{3x-3} =x[/tex]

[tex]\frac{3x^2-10x+1}{3x-3} =x[/tex]

[tex]\frac{3x^2-10x+1}{3x-3} =\frac{x(3x-3)}{3x-3}[/tex]

[tex]\frac{3x^2-10x+1}{3x-3} =\frac{3x^2-3x}{3x-3}[/tex]

[tex]3x^2-10x+1=3x^2-3x[/tex]

[tex]-10x+1=-3x[/tex]

[tex]-7x=1[/tex]

[tex]x=-1/7[/tex]

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