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Sagot :
[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]
We need to know two formulas before we start ~
- Area of circle = [tex]\sf \pi r² [/tex]
- Radius (r) = diameter (d) ÷ 2
- Circumference = [tex]\sf 2\pi r \:\: or \;\;\pi d [/tex]
Taking value of pi as 3.14
Let's solve ~
problem 1
[tex]\qquad \sf \dashrightarrow \:d = 7.4[/tex]
[tex]\qquad \sf \dashrightarrow \:r = d \div 2[/tex]
[tex]\qquad \sf \dashrightarrow \:r = 7.4 \div 2[/tex]
[tex]\qquad \sf \dashrightarrow \:r = 3.7 \: \: units[/tex]
now,
[tex]\qquad \sf \dashrightarrow \:area = 3.14 \times (3.7) {}^{2} [/tex]
[tex]\qquad \sf \dashrightarrow \:a = 42.9866 \approx43 \: \: unit {}^{2} [/tex]
problem 2
[tex]\qquad \sf \dashrightarrow \:r = 2.2 \: yd[/tex]
[tex]\qquad \sf \dashrightarrow \: circumference = 2 \times 3.14 \times 2.2[/tex]
[tex]\qquad \sf \dashrightarrow \: c =13.816 \: yd[/tex]
problem 3
[tex]\qquad \sf \dashrightarrow \:d = 5 \: cm[/tex]
[tex]\qquad \sf \dashrightarrow \:circumference = 3.14 \times 5[/tex]
[tex]\qquad \sf \dashrightarrow \:c = 15.7 \: \: cm[/tex]
problem 4
[tex]\qquad \sf \dashrightarrow \:d = 6 \: cm[/tex]
[tex]\qquad \sf \dashrightarrow \:circumference = 3.14 \times 6[/tex]
[tex]\qquad \sf \dashrightarrow \:c =18 .84 \: \: cm[/tex]
problem 5
[tex]\qquad \sf \dashrightarrow \:r = 2.1 \: m[/tex]
[tex]\qquad \sf \dashrightarrow \:area = 3.14 \times (2.1) {}^{2} [/tex]
[tex]\qquad \sf \dashrightarrow \:a = 3.14 \times 4.41[/tex]
[tex]\qquad \sf \dashrightarrow \:a \approx13.85 \: \: m {}^{2} [/tex]
problem 6
[tex]\qquad \sf \dashrightarrow \:r = 1.3 \: mm[/tex]
[tex]\qquad \sf \dashrightarrow \:c = 2 \times 3.14 \times 1.3[/tex]
[tex]\qquad \sf \dashrightarrow \:c = 8.16 \: \: mm[/tex]
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