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F(x)=2x^3-3x^2+7

F(-1)=_____
F(1)=_____
F(2)=_____

Sagot :

Answer:

f(-1)=2(-1)³-3(-1)²+7 = 2

f(1)=2(1)³-3(1)²+7 = 6

f(2)=2(2)³-3(2)²+7 = 11

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