Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
The percent yield of H₂O, if 87.0 g of H₂O is produced by combining 95.0 g of O₂ and 11.0 g of H₂ is 87.87%.
How do we calculate mass from moles?
Mass of any substance will be calculated by using their moles as:
n = W/M, where
W = given or required mass
M = molar mass
Moles of 95g of Oxygen (O₂) = 95g / 32g/mol = 2.96 moles
Moles of 11g of hydrogen (H₂) = 11g / 2g/mol = 5.5 moles
Given chemical reaction is:
2H₂ + O₂ → 2H₂O
From the stoichiometry of the reaction, it is clear that:
1 moles of O₂ = reacts with 2 moles of H₂
2.96 moles of O₂ = reacts with 2×2.96=5.92 moles of H₂
Here hydrogen is the limiting reagent as it has lower moles and formation of water depends on this only.
2 moles of H₂ = produces 2 moles of water
5.5 moles of H₂ = produces 5.5 moles of water
Mass of 5.5 moles of water will be calculated as:
W = (5.5mol)(18g/mol) = 99g
Given theoretical yield of water = 87g
% yield of water will be calculated as:
% yield = (87 / 99)×100 = 87.87%
Hence required value is 87.87%.
To know more about % yield, visit the below link:
https://brainly.com/question/25996347
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.
