callmeford
Answered

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Derive the equation of the line that goes through (−3, 1) and (0, −5).

A
y=−2x

B
y=2x−5

C
y= −2x−5

D
y=2x+5

Sagot :

semsee45

Answer:

C)  y = -2x - 5

Step-by-step explanation:

[tex]\sf let \ (x_1,y_1)=(-3,1)\\\\let \ (x_2,y_2)=(0,-5)[/tex]

[tex]\sf slope=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-5-1}{0-(-3)}=-2[/tex]

Point-slope formula: [tex]\sf y-y_1=m(x-x_1)[/tex]

[tex]\sf \implies y-1=-2(x-(-3))[/tex]

[tex]\sf \implies y=-2x-5[/tex]
  • (-3,1)
  • (0,-5)

Slope:-

  • m=-6/3=-2

Equation in point slope form

  • y-1=-2(x+3)
  • y-1=-2x-6
  • y=-2x-5
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