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NEED ASAP:
A photographer needs a frame for an 8 x 10 inch picture, such that the total area is 168 in2. Calculate the width of the frame. Which of the following quadratic equations would be used when solving this?

NEED ASAP A Photographer Needs A Frame For An 8 X 10 Inch Picture Such That The Total Area Is 168 In2 Calculate The Width Of The Frame Which Of The Following Qu class=
NEED ASAP A Photographer Needs A Frame For An 8 X 10 Inch Picture Such That The Total Area Is 168 In2 Calculate The Width Of The Frame Which Of The Following Qu class=

Sagot :

Answer:

Step-by-step explanation:

the area of this rectangle is

(10 + 2x)(8 + 2x) = 168

80 + 20x + 16x + 4x² = 168

4x² + 36x = 88

Step-by-step explanation:

A quadratic equation is an equation whose leading coefficient is of the second degree. The correct option is A.

What is a quadratic equation?

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c.

Let the width of the frame be represented by x. Therefore, the length and the breadth of the photographer be represented by (10+2x) inches and (8+2x) inches. Therefore, the total area of the photograph can be written as,

Area = Length × Breadth

168 inches² = (10+2x) inches × (8+2x)inches

168 = (10+2x)(8+2x)

168 = 80 + 20x + 16x + 4x²

0 = 80 + 20x + 16x + 4x² - 168

0 = 4x² + 36x - 88

4x² + 36x - 88 = 0

4x² + 36x = 88

Hence, the following quadratic equations that would be used when solving the width of the frame is 4x² + 36x = 88.

Learn more about Quadratic Equations:

https://brainly.com/question/2263981

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