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The chemical equation below shows the formation of aluminum oxide (al2o3) from aluminum (al) and oxygen (o2). 4al 3o2 right arrow. 2al2o3 the molar mass of o2 is 32.0 g/mol. what mass, in grams, of o2 must react to form 3.80 mol of al2o3? 60.8 grams 81.1 grams 122 grams 182 grams

Sagot :

The mass of oxygen must react to form 3.80 mol of Al₂O₃ in the given reaction is 182 grams.

How do we calculate mass from moles?

Mass of any substance will be calculated by using their moles as:

n = W/M, where

W = required mass

M = molar mass

Given chemical reaction is:

4Al + 3O₂ → 2Al₂O₃

From the stoichiometry of the reaction it is clear that,

2 moles of Al₂O₃ = obtained from 3 moles of O₂

3.80 moles of Al₂O₃ = obtained from 3/2×3.80=5.7 moles of O₂

Now we calculate the mass of oxygen of 5.7 moles as:

W = (5.7mol)(32g/mol) = 182.4 grams or 182g

Hence option (4) is correct.

To know more about moles, visit the below link:
https://brainly.com/question/26873446

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