Answered

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-2x^2+bx -5 Determine the b-value that would ensure the function has two real root.

Sagot :

mhanifa

Answer:

  • No solution

Step-by-step explanation:

Given is the quadratic function

  • y = -2x² + bx - 5

In order to have two real roots the discriminant should be posivive

  • D = - b² - 4ac
  • D = - b² - 4(-2)(-5) = - b² - 40

We need D > 0

  • -b² - 40 > 0
  • b² + 40 < 0
  • b² < - 40

There is no solution as b² is never negative

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