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2. Prison Break
A prisoner is planning to escape from prison!
The prison's gate consists of horizontal and
vertical bars that are spaced one unit apart, so
the area of each hole between the bars is 1 x 1.
The prisoner manages to remove certain bars to
make some bigger holes. Determine the area of
the largest hole in the gate after the bars are
removed.

Sagot :

lhmarianateixeira

Using the code in python we write a code to determine the prison bars and not let the prisoner escape.

How to define list in Python?

In Python, a list is represented as a sequence of objects separated by commas and enclosed in square brackets [], so an empty list, for example, can be represented by square brackets with no content.

So in an easier way we have that the code, need have vertical bars that are spaced one unit apart and determine the area of the largest hole, so:

def largestArea(N, M, H,

                V, h, v):

 s1 = set([]);

 s2 = set([]);

 for i in range(1, N + 2):

   s1.add(i);

 for i in range(1, M + 2):

   s2.add(i);

  for i in range(h):

   s1.remove(H[i]);

  for i in range( v ):

    s2.remove(V[i]);

 list1 = [0] * len(s1)

 list2 = [0]*len(s2);

  i = 0;

 for it1 in s1:

   list1[i] = it1;

   i += 1

  i = 0;

 for it2 in s2:

   list2[i] = it2

   i += 1

 list1.sort();

 list2.sort();

  maxH = 0

 p1 = 0

 maxV = 0

 p2 = 0;

 for j in range(len(s1)):

   maxH = max(maxH, list1[j] - p1);

   p1 = list1[j];

 for j in range(len(s2)):

   maxV = max(maxV, list2[j] - p2);

   p2 = list2[j];

 print((maxV * maxH))

if __name__ == "__main__":

  N = 3

 M = 3;

 H = [2]

 V = [2];

  h = len(H)

 v = len(V);

 largestArea(N, M, H, V, h, v);

See more about python at brainly.com/question/19705654

View image lhmarianateixeira
View image lhmarianateixeira
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