Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Get quick and reliable solutions to your questions from a community of experienced professionals on our platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

The perimeter of a rectangle is 120 meters and the length is 20 meters longer than the width. Find the dimensions of the rectangle. Let x = the length and y = the
2+2y = 12)
width. The corresponding modeling system is 2x + 2y =120 x-y = 20
Solve the system graphically

Sagot :

abidemiokin

The dimension of the rectangle is 40meters by 20meters

What is the perimeter of a figure?

The perimeter of a figure is the sum of all the external sides of the figure

The formula for calculating the perimeter of rectangle = 2(l+w)

If the length is 20 meters longer than the width, then;

l = 20 + w

Substitute

120 = 2(20+2w)

60 = 20 + 2w

30 = 10 + w

w = 20 meters

Since l = 20  + w

l = 20 + 20

l = 40 meters

Hence the dimension of the rectangle is 40meters by 20meters

Learn more on perimeter of figure here: https://brainly.com/question/22447290

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.