Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Which statement is true about the discontinuities of the function f(x)?
f(x)=x+1/6x^2-7x-3
There are asymptotes at x=3/2 and x=-1/3
There are holes at x = 3/2 and x = -1/3
There are asymptotes at x = -3/2 and x = 1/3
There are holes at x = -3/2 and x = 1/3

Sagot :

sqdancefan

Answer:

  (a)  There are asymptotes at x=3/2 and x=-1/3

Step-by-step explanation:

The denominator zeros can be found by factoring:

  f(x) = (x +1)/((2x -3)(3x +1))

Neither of the denominator factors is cancelled by the numerator factor, so each represents a vertical asyptote, not a function hole.

The asymptotes are at the values of x where the denominator is zero:

  2x -3 = 0   ⇒   x = 3/2

  3x +1 = 0   ⇒   x = -1/3

View image sqdancefan
We hope this was helpful. Please come back whenever you need more information or answers to your queries. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.