Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

A block of mass 3. 0 kg is hung from a spring, causing it to stretch 12 cm at equilibrium, as shown above. The 3. 0 kg block is then replaced by a 4. 0 kg block, and the new block is released from the position shown above, at which the spring is unstretched. How far will the 4. 0 kg block fall before its direction is reversed?.

Sagot :

Parrain

Based on the length of the spring and the mass of the block, the distance the 4.0 kg block can fall before a reversal in direction is 32 cm.

How do we arrive at 32cm?

Because energy is conserved, the distance the block can drop can be found as:

Mass x gravity x distance = (1 / 2) x spring constant x distance ²

Spring constant:

= (Mass x gravity)  / distance

= (3 x 9.8) / 12

= 2.45 cm

Distance is:

Mass x gravity x distance = (1 / 2) x spring constant x distance ²

distance = (2 x Mass x gravity) / spring constant

= (2 x 4 x 9.8) / 2.45

= 32 cm

Find out more on spring constants at https://brainly.com/question/1616151.

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.