Answered

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A block of mass 3. 0 kg is hung from a spring, causing it to stretch 12 cm at equilibrium, as shown above. The 3. 0 kg block is then replaced by a 4. 0 kg block, and the new block is released from the position shown above, at which the spring is unstretched. How far will the 4. 0 kg block fall before its direction is reversed?.

Sagot :

Parrain

Based on the length of the spring and the mass of the block, the distance the 4.0 kg block can fall before a reversal in direction is 32 cm.

How do we arrive at 32cm?

Because energy is conserved, the distance the block can drop can be found as:

Mass x gravity x distance = (1 / 2) x spring constant x distance ²

Spring constant:

= (Mass x gravity)  / distance

= (3 x 9.8) / 12

= 2.45 cm

Distance is:

Mass x gravity x distance = (1 / 2) x spring constant x distance ²

distance = (2 x Mass x gravity) / spring constant

= (2 x 4 x 9.8) / 2.45

= 32 cm

Find out more on spring constants at https://brainly.com/question/1616151.

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