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A 330-ohm resistor is connected to a 5-volt battery. The current through the resistor is

Sagot :

Question :-

  • A 330 Ohm Resistor is connected to a 5 Volt Battery . What is the Current through the Resistor ?

Answer :-

  • Current of the Battery is 66 Ampere.

Explanation :-

As per the provided information in the given question, The Resistance is given as 330 Ohm . The Voltage is given as 5 Volt . And, we have been asked to calculate the Current .

For calculating the Current , we will use the Formula :-

[tex] \bigstar \: \: \: \boxed{ \sf{ \: Current \: = \: \dfrac{Voltage}{Resistance} \: }} [/tex]

Therefore , by Substituting the given values in the above Formula :-

[tex] \dag \: \: \: \sf {Current \: = \: \dfrac {Voltage}{Resistance} } [/tex]

[tex] \longmapsto \: \: \: \sf {Current \: = \: \dfrac {5}{330} } [/tex]

[tex] \longmapsto \: \: \: \sf {Current \: = \: \dfrac {1}{66} } [/tex]

[tex] \longmapsto \: \: \: \textbf {\textsf {Current \: = \: 66 }} [/tex]

Hence :-

  • Current = 66 Ampere .

[tex] \underline {\rule {180pt} {4pt}} [/tex]

Additional Information :-

[tex] \Longrightarrow \: \: \: \sf {Voltage \: = \: Current \: \times \: Resistance} [/tex]

[tex] \Longrightarrow \: \: \: \sf {Current \: = \: \dfrac {Voltage}{Resistance} } [/tex]

[tex] \Longrightarrow \: \: \: \sf {Resistance \: = \: \dfrac {Voltage}{Current} } [/tex]