Answered

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A particle moves in the xy plane in a circle centered on the origin. at a certain instant the velocity and acceleration of the particle are 6. 0 m/s and (3. 0 + 4. 0) m/s2. what are the x and y coordinates of the particle at this moment?

Sagot :

onyebuchinnaji

The x and y coordinates of the particle at this moment is (6x + 4.5y) m.

Position of the particle

The position of the particle at any instant is determined from the velocity and acceleration of the particle as shown below.

v² = u² + 2as

where;

  • v is the final velocity of the particle
  • u is the initial velocity
  • a is the acceleration of the particle
  • s is the position of the particle

v² = 0 + 2as

v² = 2as

s = v²/2a

X and y - coordinates of the particle

[tex]s_x = \frac{v^2}{2a_x} = \frac{6^2}{2(3)} = 6\ m\\\\s_y = \frac{v^2}{2a_y} = \frac{6^2}{2(4)} = 4.5 \ m\\\\s = (6 x \ + 4.5y)m[/tex]

Thus, the x and y coordinates of the particle at this moment is (6x + 4.5y) m.

Learn more about position of a particle here: https://brainly.com/question/2560794

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