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Sagot :
The x and y coordinates of the particle at this moment is (6x + 4.5y) m.
Position of the particle
The position of the particle at any instant is determined from the velocity and acceleration of the particle as shown below.
v² = u² + 2as
where;
- v is the final velocity of the particle
- u is the initial velocity
- a is the acceleration of the particle
- s is the position of the particle
v² = 0 + 2as
v² = 2as
s = v²/2a
X and y - coordinates of the particle
[tex]s_x = \frac{v^2}{2a_x} = \frac{6^2}{2(3)} = 6\ m\\\\s_y = \frac{v^2}{2a_y} = \frac{6^2}{2(4)} = 4.5 \ m\\\\s = (6 x \ + 4.5y)m[/tex]
Thus, the x and y coordinates of the particle at this moment is (6x + 4.5y) m.
Learn more about position of a particle here: https://brainly.com/question/2560794
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