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I AM GIVING AWAY BRAINLIEST AND POINTS TO WHOEVER ANSWERED! PLEASE HELP!

The lengths of the diagonals of a rhombus are 2in. and 5in. Find the measures of the angles of the rhombus to the nearest degree.

Sagot :

chrisrainey

ANSWER: The four angles are:

136.4, 43.6, 136.4, and 43.6.

Draw a rhombus with the diagonals.

4 right triangles are formed.

The intersection of the diagonals of a rhombus form 90 degree (right) angles (property of a rhombus).

The diagonals of a rhombus bisect each other. This means that they cut each other in half.

So, each of the right triangles have one side = 1, one side = 2.5 and the hypotenuse = unknown (sides of the

rhombus).

Triangle 1. ABC

side a = 2.5, side b = 1

tan A = a/b = 2.5/1 = 2.5

tan A = 2.5

tan 68.2 deg = 2.5

Since, angle C = 90 and angle A = 68.2

angle B = 21.8 deg. (180 - (90 + 68.2))

Since the diagonals bisect angles in each corner of a rhombus (property of a rhombus), therefore, one corner angle is 68.2 + 68.2 = 136.4 deg. and the same side other corner angle is 21.8 + 21.8 = 43.6 deg.

Adjacent sides (ones next to each other) of a rhombus are supplementary. This means that their measures add up to 180 degrees.

Therefore, the opposite corners are

180 - 136.4 = 43.6 and

180 - 43.6 = 136.4.

So, the four angles are,

136.4, 43.6, 136.4, and 43.6

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Thanks!

Have a great day!

Mark me brainliest too!

~ms115~

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