Answer:
81 [ft].
Step-by-step explanation:
1) the basic formula is: h=gt²/2, where g - acceleration due to gravity, t - elapsed time;
2) if the final velocity is 72, g=32, then it is possible to calculate elapsed time:
[tex]t=\frac{V}{g}=\frac{72}{32}=\frac{9}{4} [sec].[/tex]
3) if g=32, t=9/4, then the required height is:
[tex]h=\frac{32*(\frac{9}{4} )^{2} }{2}=\frac{16*81}{16}=81[ft].[/tex]
The height of the building comes to be 81 feet.
Initial velocity u= 0 feet/sec
Final velocity v= 72 feet/sec
The acceleration due to gravity g =32ft /sec²
Height of the building h= suppose h
The equation of a motion is:
[tex]v^{2} =u^{2} +2gh[/tex]
Where u and v are the initial and final velocities.
[tex]72^{2} =0+2*32*h\\144 = 64h\\h=81[/tex]
So, the height of the building = 81 feet.
Therefore, the height of the building comes to be 81 feet.
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