At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
Answers:
Sample Variance = 31.03
Sample Standard Deviation = 5.57
See the table below.
===================================================
Explanation:
M refers to the midpoint of each interval. The midpoint is [tex]M = \frac{a+b}{2}[/tex] where a,b are the left and right endpoints.
For example, [tex]M = \frac{0+4}{2} = \frac{4}{2} = 2[/tex] in the first row.
Multiply the frequency with the midpoint to get the third column. Summing this column of values leads to 4+49+180+153+154 = 540 shown at the bottom of that column.
Divide this sum over the sum of the frequencies (2+7+15+9+7 = 40) and we arrive at [tex]\overline{x} = \frac{540}{40} = 13.5[/tex] which is the sample mean xbar.
--------------------------------------------------------------------------
After we determine xbar, we subtract it from each value of M. Then we square the result to get [tex](M - \overline{x})^2[/tex]. Multiply that with the column f to get the new column [tex]f(M-\overline{x})^2[/tex].
This column is added to arrive at 1210 shown in the table below. Divide this over the sum of the frequencies minus 1. So we divide by n-1 = 40-1 = 39 to get roughly 31.03
This is the sample variance.
The square root of this is sqrt(31.03) = 5.57 and this is the approximate sample standard deviation.
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.