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The functions f(x) = x2 – 1 and g(x) = –x2 + 4 are shown on the graph.

The graph shows f of x equals x squared minus 1, which is an upward opening parabola with a vertex at 0 comma negative 1 and a point at negative 1 comma 0 and a point at 1 comma 0. The graph also shows g of x, which is a downward opening parabola with a vertex at 0 comma 4 and a point at negative 1 comma 3 and a point at 1 comma 3.

Explain how to modify the graphs of f(x) and g(x) to graph the solution set to the following system of inequalities. How can the solution set be identified?

y > x2 – 1
y ≤ –x2 + 4

Sagot :

facundo3141592

We will need to shade the region above f(x) and the region below the function g(x).

How to transform the graph into the solution set?

We have:

f(x) = x^2 - 1

g(x) = -x^2 + 4

Both of these are already graphed, and we want to transform it into:

y > f(x)

y ≤ g(x)

The first inequality means that we need to graph f(x) with a dashed line, because f(x) is not part of the solution, and then we shade all the region above f(x).

For the other inequality, we use a solid line (because the points on the line are solutions) and then we shade the part below the curve.

If you want to learn more about inequalities, you can read:

https://brainly.com/question/18881247

GodOfBrainlyWorld

Answer:

The functions f(x) = x2 - 2 and g(x) = -x2 + 5 are shown on the...The functions f(x) = x2 - 2 and g(x) = -x2 + 5 are shown on the graph.

The graph shows f of x equals x squared minus 2, which is an upward opening parabola with a vertex at 0 comma negative 2 and a point at negative 1 comma negative 1 and a point at 1 comma negative 1. The graph also shows g of x,  which is a downward opening parabola with a vertex at 0 comma 5 and a point at negative 1 comma 4 and a point at 1 comma 4.

Explain how to modify the graphs of f(x) and g(x) to graph the solution set to the following system of inequalities. How can the solution set be identified?

y > x2 - 2

y ≥ -x2 + 5

Step-by-step explanation:

hope this helped!

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