Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Two forces, F1 = -3000 N and F2 = +1500 N acts on a plane horizontally. The craft is moving with a constant velocity of -850 m/s. A third force F3 is also present in the scenario but is not indicated in the image below. Find the magnitude and direction of F3

Sagot :

facundo3141592

Because the net force must be zero, we conclude that the magnitude of the force is 1500 newtons, and the direction is in the positive axis.

What is the magnitude and direction of the third force?

By Newton's laws, we know that if the net force applied to an object is different than zero, then the object is accelerated.

In this case, we know that the object moves with constant velocity, so there is no acceleration, meaning that the net force is equal to zero.

Then we must have:

F1 + F2 + F3 = 0N

Replacing F1 and F2 we get:

-3000 N + 1500N + F3 = 0

F3 = 3000N - 1500 N = 1500N

Then the magnitude of the force is 1500 newtons, and the direction is in the positive axis.

If you want to learn more about Newton's laws, you can read:

https://brainly.com/question/10454047

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.