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Sagot :
❀ Explanation -:
In this question we are provided with the length breadth and height and we are asked to find the surface area of the figure.
[tex] \small\bf{ Length = 16 \: inches } \\ \small\bf{Breadth = 7 \: inches} \\ \small\bf{Height = \: 9 \: inches} [/tex]
We know,
[tex] \pink\star \: \large\boxed{ \pink{ \rm{ Surface \: area = 2(lb + bh + hl)}}}[/tex]
Substituting the values we get
Surface area = 2(16 × 7 + 7 × 9 + 9 × 16)
= 2(112 + 63 + 144)
= 2(319)
= 638
Surface area = 638 inches².
Hey !
Question :
Find the surface area of cuboid .
Given :
- Length of Cuboid = 16 inches
- Breadth of Cuboid = 7 inches
- Height of Cuboid = 9 inches
To Find :
- We have to find the surface area of given cuboid .
Concept :
The concept of this question belongs to surface areas of different three dimensional shapes . Whether they are cuboid , cube , cylinder , cone and many more .
Formula Used :
[tex] \boxed{\sf{ \pink{Surface \: Area \: of \: cuboid=} \pink{2(lw + wh + hl)}}}[/tex]
Where ,
- l = length height of cuboid
- w = width height of cuboid
- h = height of cuboid
So Starting Our Solution :
Substituting value in formula ,
[tex] \longmapsto \: 2 ((16 \times 7) + (7 \times 9) + 9 \times 16)[/tex]
Now ,
[tex] \longmapsto \: 2(112 + 63 + 144)[/tex]
Adding the values which are inside bracket ,
[tex] \longmapsto \: 2(319)[/tex]
Now multiplying 319 by 2 ,
[tex] \longmapsto \: \bold{ 638 \: inches {}^{2} }[/tex]
Therefore ,
[tex] \boxed{ \sf \pink{Surface \: area \: of cuboid = 638 \: in {}^{2} }}[/tex]
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