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C. Test your team's method by determining the midpoint of the segment with endpoints (-5,7) and (9, 4) and checking your answer with your teacher. On a map, Cary drew a set of coordinate axes. He noticed that the town of Coyner is located at the point (3,1) and Woottonville is located at (15,7), where 1 grid unit represents 1 mile. If the towns want to place a school at the midpoint between the towns, where should it be located? How far would it be from each town?​

C Test Your Teams Method By Determining The Midpoint Of The Segment With Endpoints 57 And 9 4 And Checking Your Answer With Your Teacher On A Map Cary Drew A Se class=

Sagot :

The town should be located 13.4 units from each other

How to calculate the distance between two  points

The formula for calculating the distance between two points is expressed as:
√(x2-x1)²+(y2-y1)²

The midpoint of two coordinates is expressed as:
[tex]m(x, y)=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )[/tex]

Substitute the given coordinate

[tex]m(x, y)=(\frac{3+15}{2}, \frac{1+7}{2} )\\m(x,y)=(9,4)[/tex]

Hence the town should be located at coordinate (9, 4)

Calculate the distance

D =  √(15-3)²+(7-1)²

D =  √(12)²+(6)²

D = 13.4units

Hene the town should be located 13.4 units from each other

Learn more on midpoint here: https://brainly.com/question/24431553