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Sagot :
Answer:
r={21}
Step by Step Explanation:
PREMISES
Two times three plus a number, say, r=27
ASSUMPTIONS
Let r=the number
CALCULATIONS
The numerical expression “two times three plus a number r=27” can be denoted as:
(2×3)+r=27
6+r=27
6–6+r=27–6
0+r=27–6
r=21
PROOF
If r=21, then the equations
(2×3)+r=27
6+21=27 and
27=27 prove the root (zero) r=21 of the statement (2×3)+r=27
PREMISES
Two times three plus a number, say, r=27
ASSUMPTIONS
Let r=the number
CALCULATIONS
The numerical expression “two times three plus a number r=27” can be denoted as:
(2×3)+r=27
6+r=27
6–6+r=27–6
0+r=27–6
r=21
PROOF
If r=21, then the equations
(2×3)+r=27
6+21=27 and
27=27 prove the root (zero) r=21 of the statement (2×3)+r=27
Answer:
5 and 6
Step-by-step explanation:
let the 2 numbers be x and y , then
3x + 2y = 28 → (1)
2x + 3y = 27 → (2)
multiplying (1) by 2 and (2) by - 3 and adding will eliminate x
6x + 4y = 56 → (3)
- 6x - 9y = - 81 → (4)
add (3) and (4) term by term to eliminate x
0 - 5y = - 25
- 5y = - 25 ( divide both sides by - 5 )
y = 5
substitute y = 5 into either of the 2 equations and solve for x
substituting into (1)
3x + 2(5) = 28
3x + 10 = 28 ( subtract 10 from both sides )
3x = 18 ( divide both sides by 3 )
x = 6
The 2 numbers are 6 and 5
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