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5. The perimeter of a rectangular poultry farm is 38m. If 3 meters are subtracted from its length and 2 meters from its breadth, the length will be two times the breadth. Find the area of the farm?
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Sagot :

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By solving a system of equations we will find the dimensions of the rectangle, and with these, we will see that the area is equal to 82.31 m^2

How to find the area of the farm?

For a rectangle of length L and width W, the perimeter is:

P = 2*L + 2*W

In this case, we know that the perimeter is equal to 38m, then:

38m = 2*L + 2*W

We also know that if we subtract 3 meters from the length and 2 meters from the breadth, the length will e 2 times the breadth.

This is written as:

(L - 3m) = 2*(W - 2m)

Then we have a system of equations:

38m = 2*L + 2*W

(L - 3m) = 2*(W - 2m)

To solve this, we isolate one of the variables in one of the equations, I will isolate L on the second equation:

L = 2*(W - 2m) + 3m

Replacing that on the other equation we get:

38m = 2*(2*(W - 2m) + 3m) + 2*W

Now we can solve this for W.

38m = 4*(W - 2m) + 6m + 2*W

38m = 4*W - 2m + 2*W

38m + 2m = 6*W

40m = 6*W

40m/6 = W = 6.67m

Then the length is:

L =  2*(  6.67m - 2m) + 3m = 12.34 m

So the area of the rectangle is:

A = L*W = 12.34m*6.67m = 82.31 m^2

If you want to learn more about systems of equations, you can read:

https://brainly.com/question/13729904

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