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Sagot :
Given Information :-
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- A polygon with 10 sides ( Decagon )
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To Find :-
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- The value of one of the exterior angles
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Formula Used :-
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[tex] \qquad \diamond \: \underline{ \boxed{ \pink{ \sf Exterior ~angle = \dfrac {360^\circ}{no. ~of~sides}}}} \: \star[/tex]
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Solution :-
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Putting the given values, we get,
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[tex]\sf \dashrightarrow Exterior ~angle = \dfrac{360 ^\circ}{10} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \frac{36 \cancel{0}^\circ}{ \cancel{10}} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \underline{ \boxed{ \frak{ \red{36^\circ}}}} \: \star \\ \\ [/tex]
Thus, the value of the exterior angles of a Decagon is 36°.
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[tex] \underline{ \rule{227pt}{2pt}} \\ \\ [/tex]
Answer:
- 36° .
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Explanation :
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For a regular polygon of n sides, we have
[tex]{ \longrightarrow \qquad \pmb{ \it{Each \: exterior \: angle = { \bigg( {\dfrac{360}{n} } \bigg)^{ \circ} }}}}[/tex]
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Here, We are to find the measure of each exterior angle of a regular decagon.
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- So, we know a regular decagon has 10 sides, so n = 10 .
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Now, substituting the value :
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[tex]\sf \longrightarrow \qquad Each \: exterior \: angle_{(Decagon)} = { \bigg( {\dfrac{360}{10} } \bigg)}^{ \circ} [/tex]
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[tex]\sf \longrightarrow \qquad Each \: exterior \: angle _{(Decagon)}= { \bigg( {\dfrac{36 \cancel0}{1 \cancel0} } \bigg)}^{ \circ} [/tex]
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[tex]\sf \longrightarrow \qquad Each \: exterior \: angle_{(Decagon)} = { \bigg( {\dfrac{36}{1} } \bigg)}^{ \circ} [/tex]
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[tex]{\pmb{ \frak{ \longrightarrow \qquad Each \: exterior \: angle_{(Decagon)} = 36^{ \circ} }}}[/tex]
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Therefore,
- The measure of each exterior angle of a regular decagon is 36° .
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