In order to see whether or not a point lies on the line, we need to plug in the x-coordinate (instead of x) and plug the y-coordinate instead of y.
In this case, the x-coordinate is:-
[tex]\mathrm{1}[/tex]
and the y-coordinate is:-
[tex]\mathrm{-1}[/tex]
Plug in the values:-
[tex]\mathbf{-10(1)+5(-1)=-8}[/tex]
[tex]\mathbf{-10-5=-8}[/tex]
[tex]\mathbf{-15=-8}[/tex]
Huh?!
As you can see, we ended up with a false statement.
Hence, the answer is:-
[tex]\bigstar{\boxed{\pmb{The~point~(1,-1)~doesn't~lie~on~the~line}}}[/tex]
Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I'll comment and/or edit my answer :)
Answer:
the point (1, -1) doesn’t lie on the line (-10x + 5y = -8)
Step-by-step explanation:
Generaly , a point A(x₀ , y₀) lies on the line of equation ax + by = c
If its coordinates verify the equation which means
When we replace x by x₀ and y by y₀ in our equation we get ax₀ + by₀ = c
Then
just replace x by 1 and y by -1 in the equation: -10x + 5y = -8
We get , -10(1) + 5(-1) = -10 - 5 = -15
Since -15 ≠ -8 then (1 , -1) don’t verify the equation
Hence , the point (1, -1) doesn’t lie on the line (-10x + 5y = -8)