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Brianna has $620 to spend at a bicycle store for some new gear and biking outfits. Assume all prices listed include tax.
She buys a new bicycle for $261.04.
She buys 3 bicycle reflectors for $13.07 each and a pair of bike gloves for $13.57.
She plans to spend some or all of the money she has left to buy new biking outfits for $51.03 each.

Write and solve an inequality which can be used to determine xx, the number of outfits Brianna can purchase while staying within her budget.

Sagot :

Snor1ax

Answer: 6 outfits

Step-by-step explanation:

$620 should be greater than the price of the new bicycle + 3 * bicycle reflectors + a pair of bike gloves + unknown number of biking outfits

Therefore, the inequality will be:

620 ≥ 261.04 + 3 × 13.07 + 13.57 + 51.03x

620  ≥ 313.82 + 51.03x

[tex]\text{Solving \ for \ x}[/tex]

[tex]620\ge \:313.82+51.03x[/tex]

[tex]\mathrm{Switch\:sides}[/tex]

[tex]313.82+51.03x\le \:620[/tex]

[tex]\mathrm{Multiply\:both\:sides\:by\:}100[/tex]

[tex]313.82\cdot \:100+51.03x\cdot \:100\le \:620\cdot \:100[/tex]

[tex]\mathrm{Refine}[/tex]

[tex]31382+5103x\le \:62000[/tex]

[tex]\mathrm{Subtract\:}31382\mathrm{\:from\:both\:sides}[/tex]

[tex]31382+5103x-31382\le \:62000-31382[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]5103x\le \:30618[/tex]

[tex]\mathrm{Divide\:both\:sides\:by\:}5103[/tex]

[tex]\frac{5103x}{5103}\le \frac{30618}{5103}[/tex]

[tex]\text{Simplify}[/tex]

[tex]{x\le \:6}[/tex]

Therefore, Brianna can buy 6 or fewer outfits while staying within her budget

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