Answered

Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Question 6 (2 points) If 100.0 mL ethyl alcohol weighs 78.5 g, determine the volume in litres occupied by 1.59 kg of ethyl alcohol. Answer Instructions:​

Sagot :

Eduard22sly

The volume in litres occupied by 1.59 Kg of ethyl alcohol given the data from the question is 2.03 L

How to determine the mole of 78.5 g of ethyl alcohol

  • Mass of ethyl alcohol = 78.5 g
  • Molar mass of ethyl alcohol = 46.07 g/mol
  • Mole of ethyl alcohol =?

Mole = mass / molar mass

Mole of ethyl alcohol = 78.5 / 46.07

Mole of ethyl alcohol = 1.7 mole

How to determine the mole of 1.59 Kg of ethyl alcohol

  • Mass of ethyl alcohol = 1.59 Kg = 1.59 × 1000 = 1590 g
  • Molar mass of ethyl alcohol = 46.07 g/mol
  • Mole of ethyl alcohol =?

Mole = mass / molar mass

Mole of ethyl alcohol = 1590 / 46.07

Mole of ethyl alcohol = 34.5 moles

How to determine the new volume

  • Initial volume (V₁) = 100 mL = 100 / 1000 = 0.1 L
  • Initial mole (n₁) = 1.7
  • New mole (n₂) = 34.5 moles
  • New Volume (V₂) =.?

V₁ / n₁ = V₂ / n₂

0.1 / 1.7 = V₂ / 34.5

Cross multiply

1.7 × V₂ = 0.1 × 34.5

Divide both side by 1.7

V₂ = (0.1 × 34.5) / 1.7

V₂ = 2.03 L

Learn more about gas laws:

https://brainly.com/question/6844441

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.