shreeshaa099
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Solve:
x + 1/x = 4 1/4


Ans: 4,1/4​

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Sagot :

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Answer:

x = 4, 1/4

solving steps

[tex]\sf \rightarrow x + \dfrac{1}{x}=4\dfrac{1}{4}[/tex]

make the denominators same

[tex]\sf \rightarrow \dfrac{x(x)}{x} + \dfrac{1}{x}=4\dfrac{1}{4}[/tex]

simplify the following

[tex]\sf \rightarrow \dfrac{x^2}{x} + \dfrac{1}{x}=\dfrac{17}{4}[/tex]

join both fractions together

[tex]\sf \rightarrow \dfrac{x^2+1}{x}=\dfrac{17}{4}[/tex]

cross multiply

[tex]\sf \rightarrow 4(x^2+1)=17(x)[/tex]

simplify

[tex]\sf \rightarrow 4x^2-17(x)+4=0[/tex]

completing square

[tex]\sf \rightarrow 4x^2-16(x)-x+4=0[/tex]

factor

[tex]\sf \rightarrow 4x(x-4)-1(x-4)=0[/tex]

group the variables

[tex]\sf \rightarrow (4x-1)(x-4)=0[/tex]

simplify

[tex]\sf \rightarrow (x-4)=0, \ (4x-1) =0[/tex]

final answer

[tex]\sf \rightarrow x=4, \ x =\dfrac{1}{4}[/tex]

Answer:

[tex]\boxed{x = \dfrac{1}{4}}[/tex] and [tex]\boxed{x = 4}[/tex]

Step-by-step explanation:

Given equation:

[tex]x + \dfrac{1}{x} = 4\dfrac{1}{4}[/tex]

Step-1: Convert the mixed fraction on the R.H.S into improper fraction

[tex]x + \dfrac{1}{x} = 4\dfrac{1}{4}[/tex]

[tex]x + \dfrac{1}{x} = \dfrac{4 \times4 + 1}{4}[/tex]

[tex]x + \dfrac{1}{x} = \dfrac{16 + 1}{4}[/tex]

[tex]x + \dfrac{1}{x} = \dfrac{17}{4}[/tex]

Step-2: Make common denominators on the L.H.S:

[tex]x + \dfrac{1}{x} = \dfrac{17}{4}[/tex]

[tex]\dfrac{x^{2} }{x} + \dfrac{1}{x} = \dfrac{17}{4}[/tex]

Step-3: Combine the denominators on the L.H.S

[tex]\dfrac{x^{2} }{x} + \dfrac{1}{x} = \dfrac{17}{4}[/tex]

[tex]\dfrac{x^{2} +1}{x} = \dfrac{17}{4}[/tex]

Step-4: Use cross multiplication

[tex]\dfrac{x^{2} +1}{x} = \dfrac{17}{4}[/tex]

[tex]x^{2} +1} = \dfrac{17x}{4}[/tex]

[tex]4(x^{2} +1}) = {17x}[/tex]

Step-5: Simplify the distributive property

[tex]4(x^{2} +1}) = {17x}[/tex]

[tex]4x^{2} +4} = {17x}[/tex]

[tex]-17x + 4x^{2} +4} = 0[/tex]

Step-6: Change "-17x" to "-16x - x" as it is equivalent

[tex]-17x + 4x^{2} +4} = 0[/tex]

[tex](-16x - x) + 4x^{2} +4} = 0[/tex]

Step-7: Factor the common terms

[tex](-16x - x) + 4x^{2} +4} = 0[/tex]

[tex]-16x - x + 4x^{2} +4} = 0[/tex]

[tex]4x(-4 + x) - 1(x - 4) = 0[/tex]

Step-8: Group the terms

[tex]4x(-4 + x) - 1(x - 4) = 0[/tex]

[tex](x - 4)(4x - 1) = 0[/tex]

Step-9i: Use cross multiplication for (x - 4)

[tex](x - 4)(4x - 1) = 0[/tex]

[tex]x - 4 = \dfrac{0}{4x - 1 } = 0[/tex]

Step-9ii: Use cross multiplication for (4x - 1)

[tex](x - 4)(4x - 1) = 0[/tex]

[tex]4x - 1 = \dfrac{0}{x - 4} = 0[/tex]

Thus [tex]x - 4 = 0[/tex] and [tex]4x - 1 = 0[/tex].

Step-10: Simplify both equations

[tex]4x - 1 = 0[/tex]                  [tex]x - 4 = 0[/tex]

[tex]4x = 0 + 1[/tex]                  [tex]x = 0 + 4[/tex]

[tex]4x = 1[/tex]                          [tex]\boxed{x = 4}[/tex]

[tex]\boxed{x = \dfrac{1}{4}}[/tex]

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