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Sagot :
To prepare 0.250 M solution, the 0.0667 mol of KCl should be diluted up to 266.8mL
Stoichiometry
From the question,
We are to determine to what volume the KCl should be diluted, in order to prepare 0.250 M solution
From the formula,
Numer of moles = Concentration × Volume
Then, we can write that
[tex]Volume= \frac{Number\ of\ moles}{Concentration }[/tex]
From the given information,
Number of moles = 0.0667 mole
Concentration = 0.250 M
Then,
[tex]Volume = \frac{0.0667}{0.250}[/tex]
Volume = 0.2668 L
Volume = 266.8 mL
Hence, to prepare 0.250 M solution, the 0.0667 mol of KCl should be diluted up to 266.8mL
Learn more on Stoichiometry here: https://brainly.com/question/16632398
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