Answered

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To what volume should 0.0667 mol of KCl be diluted in order to prepare a 0.250 M solution?

Sagot :

To prepare 0.250 M solution, the 0.0667 mol of KCl should be diluted up to 266.8mL

Stoichiometry

From the question,

We are to determine to what volume the KCl should be diluted, in order to prepare 0.250 M solution

From the formula,

Numer of  moles = Concentration × Volume

Then, we can write that

[tex]Volume= \frac{Number\ of\ moles}{Concentration }[/tex]

From the given information,

Number of moles = 0.0667 mole

Concentration = 0.250 M

Then,

[tex]Volume = \frac{0.0667}{0.250}[/tex]

Volume = 0.2668 L

Volume = 266.8 mL

Hence, to prepare 0.250 M solution, the 0.0667 mol of KCl should be diluted up to 266.8mL

Learn more on Stoichiometry here: https://brainly.com/question/16632398

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