Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

What is the ph of a solution made by mixing 30.00 ml of 0.10 m acetic acid with 50.00 ml of 0.100 m koh? assume that the volumes of the solutions are additive. k a = 1.8 × 10-5 for ch3co2h.

Sagot :

ogorwyne

Given 30.00 ml of 0.10 m acetic acid and 50.00 ml of 0.100 m koh, the pH of the solution is 12.40

What is the pH of a substance?

This is the measure of the acidity or the basicity of an aqueous or liquidsolution.

The details that are contained in this question are:

Mole of CH3COOH = 0.1 M

Volume of CH3COOH  = 30 mL

Mole of KOH = 0.1 M

Volume of KOH = 50 mL

mol of (CH3COOH) = 0.1 Mole * 30 mL = 3 mol

mol of (KOH) = 0.1 Mole * 50 mL = 5 mol

From the solution above,

mol of CH3COOH = 3 mol

mol of KOH = 5 mol

3 mol of both substances is going to react

excess KOH remaining = 5 - 3 =  2 mmol

Volume of both Solutions

= 30 + 50 = 80 mL

OH⁻ = 2/80

= 0.025 M

use:

pOH = -log [OH-]

= -log (0.025)

pOH = 1.602

PH = 14 - pOH

= 14 - 1.60

= 12.40

The calculated pH is therefore 12.40

Read more on pH here: https://brainly.com/question/22390063

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.