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Sagot :
Answer:
As per Provided Information
- Mass of car m is 1400Kg
- Initial velocity u is 13m/s
- Time taken to stop t is 5 second .
- Final velocity v is 0m/s
we have been asked to determine the force applied to stop the car. First we will calculate the acceleration of the car.
[tex] \boxed{\bf \: a \: = \dfrac{(v - u)}{t}}[/tex]
Substituting the value and let's solve it
[tex] \longrightarrow\sf \: a \: = \dfrac{0 - 13}{5} \\ \\ \\ \longrightarrow\sf \: a \: = \cfrac{ - 13}{5} \\ \\ \\ \longrightarrow\sf \: a \: = - 2.6 \: {ms}^{ - 2} [/tex]
Now, let's calculate the force applied to stop the car .
[tex] \pink{\boxed{\bf \: F = ma}}[/tex]
Substituting the value we get
[tex] \longrightarrow \sf \: F = 1400 \times ( - 2.6) \\ \\ \\ \longrightarrow \sf \: F = - 3640 \: N[/tex]
Here , negative sign show that the " Force is acting in opposite direction of the motion"
Therefore,
- 3640 Newton force is required to stop the car .
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