katieh8
Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

what force much be applied to stop a 1400kg car that is initially traveling at 13 m/s over a 5 second time period

Sagot :

Answer:

As per Provided Information

  • Mass of car m is 1400Kg
  • Initial velocity u is 13m/s
  • Time taken to stop t is 5 second .
  • Final velocity v is 0m/s

we have been asked to determine the force applied to stop the car. First we will calculate the acceleration of the car.

[tex] \boxed{\bf \: a \: = \dfrac{(v - u)}{t}}[/tex]

Substituting the value and let's solve it

[tex] \longrightarrow\sf \: a \: = \dfrac{0 - 13}{5} \\ \\ \\ \longrightarrow\sf \: a \: = \cfrac{ - 13}{5} \\ \\ \\ \longrightarrow\sf \: a \: = - 2.6 \: {ms}^{ - 2} [/tex]

Now, let's calculate the force applied to stop the car .

[tex] \pink{\boxed{\bf \: F = ma}}[/tex]

Substituting the value we get

[tex] \longrightarrow \sf \: F = 1400 \times ( - 2.6) \\ \\ \\ \longrightarrow \sf \: F = - 3640 \: N[/tex]

Here , negative sign show that the " Force is acting in opposite direction of the motion"

Therefore,

  • 3640 Newton force is required to stop the car .

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.