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Sagot :
Answer:
x ≥ 5
Step-by-step explanation:
[tex]\sf 4x+3\ge \:23[/tex]
subtract 3 from both sides
[tex]\sf 4x+3-3\ge \:23-3[/tex]
simplify
[tex]\sf 4x\ge \:20[/tex]
divide both sides by 5
[tex]\sf \dfrac{4x}{4}\ge \dfrac{20}{4}[/tex]
simplify
[tex]\sf x\ge \:5[/tex]
Answer:
x ≥ 5
Step-by-step explanation:
To simplify the given inequality, we need to isolate the variable "x".
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Step-1: Subtract 3 both sides
4x + 3 ≥ 23
⇒ 4x + 3 - 3 ≥ 23 - 3
⇒ 4x ≥ 23 - 3
⇒ 4x ≥ 20
Step-2: Divide 4 both sides
⇒ 4x ≥ 20
⇒ 4x/4 ≥ 20/4
⇒ x ≥ 5
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(Note: The solution of the book you provided in your question is incorrect. Seek below for proof)
*answer is x is greater than or equal to 3.*
Substituting 3 in the inequality:
4x + 3 ≥ 23
4(3) + 3 ≥ 23
12 + 3 ≥ 23
15 ≥ 23 (False)
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