The amount of water that the cylindrical shaped silo can hold is 324π ft³.
Given the data in the question;
- Diameter of the cylindrical silo; [tex]D = 18ft[/tex]
- Radius; [tex]r = \frac{D}{2} = \frac{18ft}{2} = 9ft[/tex]
- Height of the silo; [tex]h = 4ft[/tex]
- Volume of the silo in terns of [tex]\pi[/tex]; [tex]V = \ ?[/tex]
Volume
The volume of a cylinder simply signfies the amount of space in, i.e the quanity of materials it can carry or hold.
The volume of a cylinder is expressed as;
[tex]V = \pi r^2h[/tex]
To determine the amount of water the silo can hold, we substitute our given values into the expression above.
[tex]V = \pi r^2h\\\\V = \pi * (9ft)^2 * 4ft\\\\V = \pi * 324ft^2\\\\V = 324\pi ft^2[/tex]
Option B) 324π ft³ is the correct answer.
Hence, the amount of water that the cylindrical shaped silo can hold is 324π ft³.
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