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How many joules are required to eat 5.25 g of titanium from 85.5 celsius to 132.5 celsius

Sagot :

The amount of energy required to eat 5.25 g of Titanium from 85.5 celsius to 132.5 celsius is 129 joules.

How do we calculate required heat?

Absorbed or released amount of heat will be calculated by using the below formula as:

Q = mcΔT, where

m = mass of titanium = 5.25g

c = specific heat of titanium = 0.523 J/gram degree celsius

ΔT = change in temperature = 132.5 - 85.5 = 47 degree celsius

On putting these values on the above equation we get,

Q = (5.25)(0.523)(47) = 129 joules

Hence required heat is 129 joules.

To know more about absorbed heat, visit the below link:

https://brainly.com/question/8828503


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