Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Find the dimensions of a rectangle (in m) with perimeter 68 m whose area is as large as possible. (enter the dimensions as a comma-separated list.)

Sagot :

The dmension of the rectangle with perimeter of 68 m has the largest possible area as 17m by 17m.

Perimeter of a rectangle

perimeter of rectangle = 2(l + w)

where

  • l = length
  • w = width

Therefore,

perimeter = 68 m

68 = 2l + 2w

l + w = 34

l = 34 - w

Hence, the largest possible area is at the amximum.

area = lw

area = w(34 - w)

area = 34w - w²

The maximum is at dA / dw = 0

Therefore,

34 - 2w  = 0

2w = 34

w = 34 / 2

w = 17

l + w = 34

l + 17 = 34

l = 34 - 17

l = 17

area = 17² = 289 m²

learn more on rectangle here:https://brainly.com/question/17076667

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.