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Sagot :
✰ Given Information :-
⠀
A cylinder with following dimensions :
- Radius = 3 inches
- Height = 5 inches
⠀
✰ To Find :-
⠀
- The volume of the cylinder
⠀
✰ Formula Used :-
⠀
[tex] \qquad \star \: \underline{ \boxed{ \purple{\sf Volume_{Cylinder} = \pi {r}^{2} h}}} \: \star[/tex]
⠀
Where,
- r = radius
- h = height
⠀
✰ Solution :-
⠀
Putting the values in the formula, we get,
⠀
[tex] \sf \longrightarrow Volume=3.14 \times {(3)}^{2} \times 5 \\ \\ \\ \sf \longrightarrow Volume=3.14 \times 45 \: cm \: \: \: \: \: \\ \\ \\ \sf \longrightarrow \underline{ \boxed{ \green{ \frak{Volume= {141 .3 \: cm}^{3} }}}} \: \star \: \: \: \: \: \\ [/tex]
⠀
Thus, the volume of the cylinder is 141.3 cm³.
⠀
[tex] \underline{ \rule{230pt}{2pt}} \\ \\ [/tex]
Step-by-step explanation:
As it is given that, a cylinder has radius 3 inches and height 5 inches and we are to find the volume of the cylinder, also a extra information is given that is a cone has the same radius and height.
[tex] \: [/tex]
We know,
[tex]{ \longrightarrow\qquad{\frak {\pmb{Volume_{(cylinder) } = \pi {r}^{2}h }}}} \\ \\[/tex]
Where,
- r is the radius of the cylinder.
- h is the height of the cylinder.
- Here, we will take the value of π as 3.14 approximately .
[tex] \: [/tex]
Now, we will substitute the given values in the formula :
[tex] \: [/tex]
[tex]{ \longrightarrow\qquad{\sf {\pmb{Volume_{(cylinder) } = 3.14 \times ( {3})^{2} \times 5 }}}} \\ \\[/tex]
[tex]{ \longrightarrow\qquad{\sf {\pmb{Volume_{(cylinder) } = 3.14 \times 9 \times 5 }}}} \\ \\[/tex]
[tex]{ \longrightarrow\qquad{\sf {\pmb{Volume_{(cylinder) } = 3.14 \times 45 }}}} \\ \\[/tex]
[tex]{ \longrightarrow\qquad{\frak {\pmb{Volume_{(cylinder) } = 141.3 }}}} \\ \\[/tex]
Note :
- Answer might be different if we take the value of π as 22/7 .
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