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Evaluate arithmetic series:-

Step-by-step answer, please!

Evaluate Arithmetic Series Stepbystep Answer Please class=

Sagot :

Let's see

[tex]\\ \rm\Rrightarrow {\displaystyle{\sum^{275}_{k=1}}}(-5k+12)[/tex]

[tex]\\ \rm\Rrightarrow (-5(1)+12)+(-5(2)+12)\dots (-5(275)+12)[/tex]

[tex]\\ \rm\Rrightarrow 7+5+3+2+1+\dots -1363[/tex]

So

  • a=7
  • l=-1363
  • n=275

Sum:-

[tex]\\ \rm\Rrightarrow S_n=\dfrac{n}{2}[a+l][/tex]

[tex]\\ \rm\Rrightarrow \dfrac{275}{2}(7-1363)[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{275}{2}(-1356)[/tex]

[tex]\\ \rm\Rrightarrow 275(-678)[/tex]

[tex]\\ \rm\Rrightarrow -186450[/tex]

semsee45

Answer:

-186,450

Step-by-step explanation:

Sum of arithmetic series formula

[tex]S_n=\dfrac{n}{2}[2a+(n-1)d][/tex]

where:

  • a is the first term
  • d is the common difference between the terms
  • n is the total number of terms in the sequence

[tex]\displaystyle \sum\limits_{k=1}^{275} (-5k+12)[/tex]

To find the first term, substitute [tex]k = 1[/tex] into [tex](-5k+12)[/tex]

[tex]a_1=-5(1)+12=7[/tex]

To find the common difference, find [tex]a_2[/tex] then subtract [tex]a_1[/tex] from [tex]a_2[/tex]:

[tex]a_2=-5(2)+12=2[/tex]

[tex]\begin{aligned}d & =a_2-a_1\\ & =2-7\\ & =-5\end{aligned}[/tex]

Given:

  • [tex]a=7[/tex]
  • [tex]d=-5[/tex]
  • [tex]n=275[/tex]

[tex]\begin{aligned}S_{275} & = \dfrac{275}{2}[2(7)+(275-1)(-5)]\\& = \dfrac{275}{2}[14-1370]\\& = \dfrac{275}{2}[-1356]\\& = -186450\end{aligned}[/tex]

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