Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

A spring with spring constant 0.5 m has a force of 40 newtons applied to it. How much does the spring
stretch? Use Hooke's law F = kx
N
O A 1,600 cm
OB. 100 cm
O C. 80 cm
O D. 40 cm

Sagot :

abidemiokin

The spring stretch by 80cm if a spring constant 0.5 m has a force of 40 newtons applied to it

How to calculate the force acting on string?

According to Hookes law

F = ke

where

F is the applied force = 40N

k is the spring constant

e is the extension  = 0.5

Substitute

40 = 0.5e

e = 40/0.5

e = 80cm

Hence the spring stretch by 80cm if a spring constant 0.5 m has a force of 40 newtons applied to it

Learn more on hookes law here: https://brainly.com/question/12253978

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.