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A spring with spring constant 0.5 m has a force of 40 newtons applied to it. How much does the spring
stretch? Use Hooke's law F = kx
N
O A 1,600 cm
OB. 100 cm
O C. 80 cm
O D. 40 cm

Sagot :

abidemiokin

The spring stretch by 80cm if a spring constant 0.5 m has a force of 40 newtons applied to it

How to calculate the force acting on string?

According to Hookes law

F = ke

where

F is the applied force = 40N

k is the spring constant

e is the extension  = 0.5

Substitute

40 = 0.5e

e = 40/0.5

e = 80cm

Hence the spring stretch by 80cm if a spring constant 0.5 m has a force of 40 newtons applied to it

Learn more on hookes law here: https://brainly.com/question/12253978

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