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What is the sequence of transformations that maps δpqr onto δp’q’r’? use the drop-down menus to explain your answer. triangles p q r and p prime q prime and r prime on a coordinate plane. the smaller triangle has coordinates p negative 1 comma 1, q negative 2 comma 3, and r negative 2.5 comma 1. the larger triangle has coordinates p prime 2 comma 2, q prime 4 comma 6, and r prime 5 comma 2. a dilation with center (0, 0), a scale factor choose... , and a reflection across the choose... .

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MrRoyal

The sequence of transformation is:

a dilation with center (0, 0), a scale factor 2, and a reflection across the y-axis

How to determine the sequence of transformation?

The coordinates are given as:

p = (-1, 1)

q = (-2, 3)

r = (-2.5, 1)

p' = (2 , 2)

q' = (4, 6)

r' = (5, 2)

Start by reflecting the triangle pqr across the y-axis.

The transformation rule is:

[tex](x,y) \to (-x,y)[/tex]

So, we have:

p = (1, 1)

q = (2, 3)

r = (2.5, 1)

Dilate the resulting by a scale factor of 2 with the center of (0, 0)

The transformation rule is:

(x,y) = 2(x,y)

So, we have:

p' = (2 , 2)

q' = (4, 6)

r' = (5, 2)

Hence, the sequence of transformation is:

a dilation with center (0, 0), a scale factor 2, and a reflection across the y-axis

Read more about transformation at:

https://brainly.com/question/4289712

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