Answered

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The line L passes through the points (5, -5) and (1, 2).
Find the gradient of line L.

Sagot :

fieryanswererft

gradient of L = -7/4

Explanation:

[tex]\sf gradient = \dfrac{y_2-y_1}{x_2-x_1}[/tex]

Insert the following values.

[tex]\rightarrow \sf \dfrac{2-(-5)}{1-5}[/tex]

[tex]\rightarrow \sf \dfrac{7}{-4}[/tex]

[tex]\rightarrow \sf -\dfrac{7}{4}[/tex]

hello!

Use the slope formula:-

(the slope is the same as the gradient)

[tex]\sf{\displaystyle\frac{y2-y1}{x2-x1} }[/tex]

[tex]\sf{\displaystyle\frac{2-(-5)}{1-5}}[/tex]

[tex]\sf{\displaystyle\frac{2+5}{-4} }=\frac{7}{-4} ={\boxed{-\frac{7}{4} }}\leftarrow\sf{slope~of~line~L}}}[/tex]

note:-

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)

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