Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

a survey of lobster fishermen found that they catch an average of 32 pounds of lobster per day with a standard deviation of 4 pounds. if a random sample of 36 lobster fishermen is selected, what is the possibility that their average catch is less than 31.5 pounds? assume the distribution of weights of lobster is normal

Sagot :

raphealnwobi

There is a probability of 22.66% that their average catch is less than 31.5 pounds

What is z score?

The z score is used to determine by how many standard deviations the raw score is above or belaw the mean. It is given by:

z = (raw score  - mean)/ (standard deviation ÷ √sample)

Given that, mean = 32, std = 4, sample = 36, hence:

For 31.5:

z = (31.5 - 32) / (4 ÷√36) = -0.75

P(z < -0.75) = 0.2266

There is a probability of 22.66% that their average catch is less than 31.5 pounds

Find out more on z score at: https://brainly.com/question/25638875

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.