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a survey of lobster fishermen found that they catch an average of 32 pounds of lobster per day with a standard deviation of 4 pounds. if a random sample of 36 lobster fishermen is selected, what is the possibility that their average catch is less than 31.5 pounds? assume the distribution of weights of lobster is normal

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There is a probability of 22.66% that their average catch is less than 31.5 pounds

What is z score?

The z score is used to determine by how many standard deviations the raw score is above or belaw the mean. It is given by:

z = (raw score  - mean)/ (standard deviation ÷ √sample)

Given that, mean = 32, std = 4, sample = 36, hence:

For 31.5:

z = (31.5 - 32) / (4 ÷√36) = -0.75

P(z < -0.75) = 0.2266

There is a probability of 22.66% that their average catch is less than 31.5 pounds

Find out more on z score at: https://brainly.com/question/25638875

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