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Sagot :
Answer:
[tex]\sf x^2+y^2=37[/tex]
Step-by-step explanation:
Equation of a circle: [tex]\sf(x-h)^2+(y-k)^2=r^2[/tex]
where (h, k) is the center and r is the radius
Given the center is at (0, 0)
[tex]\sf \implies (x-0)^2+(y-0)^2=r^2[/tex]
[tex]\sf \implies x^2+y^2=r^2[/tex]
Given the circle passes through point (1, -6):
[tex]\sf \implies (1)^2+(-6)^2=r^2[/tex]
[tex]\sf \implies r^2=37[/tex]
Therefore, the equation of the circle is:
[tex]\sf \implies x^2+y^2=37[/tex]
Equation of a circle passing through origin
- x²+y²=r²
So
As (1,-6) lies on circle it will satisfy
- 1²+(-6)²=r^2
- 1+36=r²
- r²=37
Now
equation of the circle
- x²+y²=37
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