The actual roots of the function P(x) = x^4 - 4x^3 - 4x^2 + 36x - 45 are its real roots
The actual roots ordered from least to greatest are -3 and 3
How to determine the actual roots?
From the complete question, the polynomial function is:
P(x) = x^4 - 4x^3 - 4x^2 + 36x - 45
Expand the above equation
P(x) = x^4 - 4x^3 + 5x^2 - 9x^2 + 36x - 45
Factorize the equation
P(x) = x^2(x^2 - 4x + 5) - 9(x^2 - 4x + 5)
Factor out x^2 - 4x + 5
P(x) = (x^2- 9)(x^2 - 4x + 5)
Express x^2 - 9 as a difference of two squares
P(x) = (x + 3)(x - 3)(x^2 - 4x + 5)
The expression (x^2 - 4x + 5) cannot be factorized.
So, we have:
P(x) = (x + 3)(x -3)
Equate to 0
(x + 3)(x -3) = 0
Expand
x + 3 = 0 or x - 3 = 0
Solve for x
x = -3 or x = 3
Hence, the actual roots ordered from least to greatest are -3 and 3
Read more about polynomial functions at:
https://brainly.com/question/2833285
