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The possible rational roots are ±1, ±3, ±5, ±9, ±15, and ±45.
The actual roots ordered from least to greatest are?

Sagot :

MrRoyal

The actual roots of the function P(x) = x^4 - 4x^3 - 4x^2 + 36x - 45 are its real roots

The actual roots ordered from least to greatest are -3 and 3

How to determine the actual roots?

From the complete question, the polynomial function is:

P(x) = x^4 - 4x^3 - 4x^2 + 36x - 45

Expand the above equation

P(x) = x^4 - 4x^3 + 5x^2 - 9x^2 + 36x - 45

Factorize the equation

P(x) = x^2(x^2 - 4x + 5) - 9(x^2 - 4x + 5)

Factor out x^2 - 4x + 5

P(x) = (x^2- 9)(x^2 - 4x + 5)

Express x^2 - 9 as a difference of two squares

P(x) = (x + 3)(x - 3)(x^2 - 4x + 5)

The expression (x^2 - 4x + 5) cannot be factorized.

So, we have:

P(x) = (x + 3)(x -3)

Equate to 0

(x + 3)(x -3) = 0

Expand

x + 3 = 0 or x - 3 = 0

Solve for x

x = -3 or x = 3

Hence, the actual roots ordered from least to greatest are -3 and 3

Read more about polynomial functions at:

https://brainly.com/question/2833285

kristentylerr1

Answer:

answer in picture

Step-by-step explanation:

View image kristentylerr1
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