Consider these equations: 2S(s)+3O2(g)→2SO3(g) , ΔH=−792kJ 2S(s)+2O2(g)→2SO2(g) , ΔH=−594kJ 2SO2(g)+O2(g)→2SO3(g) , ΔH=? What is the missing ΔH ? −294kJ −198kJ +198kJ +294kJ

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kb345190645 kb345190645

06-04-2022
Chemistry

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Consider these equations: 2S(s)+3O2(g)→2SO3(g) , ΔH=−792kJ 2S(s)+2O2(g)→2SO2(g) , ΔH=−594kJ 2SO2(g)+O2(g)→2SO3(g) , ΔH=? What is the missing ΔH ? −294kJ −198kJ +198kJ +294kJ

Sagot :

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pstnonsonjoku pstnonsonjoku · Answer 1 · 2022-04-14T05:17:24-04:00

Hess law can help us to obtain the enthalpy of a series of reactions by summation. The missing enthalpy of this reaction is −198kJ.

What is Hess law?

According to the Hess law of constant heat summation, the enthalpy of a sequence of reactions can be obtained as the sum of the enthalpies of all the reactions.

Now looking at all the reavtion written here in order to obtain the missing enthalpy, we conclude that the missing enthalpy is −198kJ.

Learn more about enthalpy: https://brainly.com/question/3393755

aghajaniedna aghajaniedna · Answer 2 · 2022-07-20T16:31:05-04:00

aghajaniedna aghajaniedna

20-07-2022

2SO2 (g) + O2 (g)→2SO3 (g), ΔH = −198 kJ.

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Consider these equations: 2S(s)+3O2(g)→2SO3(g) , ΔH=−792kJ 2S(s)+2O2(g)→2SO2(g) , ΔH=−594kJ 2SO2(g)+O2(g)→2SO3(g) , ΔH=? What is the missing ΔH ? −294kJ −198kJ +198kJ +294kJ

Sagot :

What is Hess law?

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