meredith48034
Answered

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NO LINKS!! Explain your answer (show the support by showing the changes in x and y on your table). If the relationship is linear, inverse, or exponential, write the equation.
#7 and #8​

NO LINKS Explain Your Answer Show The Support By Showing The Changes In X And Y On Your Table If The Relationship Is Linear Inverse Or Exponential Write The Equ class=

Sagot :

sqdancefan

Answer:

  7. inverse relationship; equation: y = 16/x

  8. no relationship; no equation

Step-by-step explanation:

The attachment shows the support for the conclusions. The relationship can be chosen from those offered by looking at differences, ratios, or products of y-values for sequential x-values.

  • linear: constant differences
  • exponential: constant ratios
  • inverse: constant products

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7.

In the first problem, we note that the relationship between y-values varies inversely as the relationship between x-values: when x goes up by a factor of (n+1)/n, the value of y goes down by its inverse factor: n/(n+1). That same relationship is observed by noting that the product of x and y is a constant, 16.

 relationship: inverse

  y = 16/x

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8.

As we looked at the table, we thought this might be an exponential function. Each y-value seemed to be twice the one before—until we got to x=5. As x went from 4 to 5, the y-value increased by a factor of 16, not 2. This means there is no simple relationship between x and y, and no simple equation that will describe the sequence of y-values.

View image sqdancefan
semsee45

Answer:

Linear relationship: increasing or decreasing one variable will cause a corresponding increase or decrease in the other variable.

Inverse relationship:  the value of one variable decreases as the value of the other variable increases.

Exponential relationship: a constant change in the independent variable (x) gives the same proportional change in the dependent variable (y)

Question 7

As the x-value increases (by one unit), the y-value decreases.

Therefore, this is an inverse relationship.

The y-values are calculated by dividing 16 by the x-value.

[tex]\sf y=\dfrac{16}{x}[/tex]

Question 8

As the x-value increases, the y-value increases.  

The y-value increases by a factor of 2 for each x-value increase of 1 unit from 1 ≤ x ≤ 4 and 5 ≤ x ≤ 6.

[tex]\sf y=2^x \ for \ 1\leq x\leq 4[/tex]

[tex]\sf y=2^{(x+3)} \ for \ 5\leq x \leq 6[/tex]

These are separate exponential relations for restricted domains.

So there doesn't appear to be one relationship for a non-restricted domain.

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