Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

If the poh of vinegar is 9.45, what is its [oh− ]? round to the nearest hundredth. × 10n m n =

Sagot :

abidemiokin

The [OH] of vinegar to the  nearest hundredth is 2.82 * 10^-5

How to calculate the [OH] of a substance:

The sum of the pH and pOH of a substance is 14. Mathematically

[OH−] = Antilog (pOH)

Given the following parameters

[OH−] = Antilog (9.45)

Substitute

[OH−] = 2.82 * 10^-5

Hence the [OH] of vinegar to the  nearest hundredth is 2.82 * 10^-5

Learn more on pH and pOH here:https://brainly.com/question/13557815

h00dmadeasia66

Answer:

The person above me is incorrect

1st blank is 3.55

2nd blank is -10

Step-by-step explanation:

Look at the image (bottom left corner)

View image h00dmadeasia66
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.